hasil dari y=x²-3×+2
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[tex]y=x ^ { 2 } -3x+2 \\ x^{2}-3x+2=y \\ x^{2}-3x+2-y=0 \\ x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\left(2-y\right)}}{2} \\ x=\frac{-\left(-3\right)±\sqrt{9-4\left(2-y\right)}}{2} \\ x=\frac{-\left(-3\right)±\sqrt{9+4y-8}}{2} \\ x=\frac{-\left(-3\right)±\sqrt{4y+1}}{2} \\ x=\frac{3±\sqrt{4y+1}}{2} \\ x=\frac{\sqrt{4y+1}+3}{2} [/tex]
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[tex]x=\frac{\sqrt{4y+1}+3}{2} \\ x=\frac{-\sqrt{4y+1}+3}{2} [/tex]
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[tex]y=\left(x-2\right)\left(x-1\right) \\ y\geq -\frac{1}{4}[/tex]
[answer.2.content]
